The present ages of A, B and C are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. What are their present ages (in years)?Options16, 30, 4016, 28, 3616, 28 , 4516, 28 40
Question
The present ages of A, B and C are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. What are their present ages (in years)?Options16, 30, 4016, 28, 3616, 28 , 4516, 28 40
Solution
Let's solve this step by step:
Step 1: Let's assume the present ages of A, B, and C are 4x, 7x, and 9x respectively.
Step 2: According to the problem, eight years ago, the sum of their ages was 56. So, we can write the equation as (4x - 8) + (7x - 8) + (9x - 8) = 56.
Step 3: Simplifying the equation, we get 20x - 24 = 56.
Step 4: Solving for x, we get x = 4.
Step 5: Substituting x = 4 in 4x, 7x, and 9x, we get the present ages of A, B, and C as 16, 28, and 36 respectively.
So, the correct option is 16, 28, 36.
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