1. How many three different digit numbers could be formed from the set ofDigits {1, 3, 6, 7}?(a) 9 (b) 12 (c) 64 (d) 24

The solution to this problem involves the concept of permutations.

Step 1: Understand the problem We are asked to find out how many three-digit numbers can be formed from the set of digits {1, 3, 6, 7}. The numbers must be different and the digits in the numbers must also be different.

Step 2: Apply the concept of permutations In permutations, the order of the digits matters. For a three-digit number, we have three places to fill: the hundreds place, the tens place, and the ones place.

Step 3: Calculate the permutations For the hundreds place, we have 4 choices (1, 3, 6, or 7). After filling the hundreds place, we have 3 choices left for the tens place. And after filling the tens place, we have 2 choices left for the ones place.

So, the total number of different three-digit numbers that can be formed is 432 = 24.

Therefore, the answer is (d) 24.