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PASSAGEDirections Read the given passage carefully and find the answers of following questions. LCM of two numbers A and B is 60. B is a 2-digit number which leaves remainder as 2 when divided by 6. It is also given B>A.Read the instructions carefullyFind Maximum value of A+B.OPTIONS23323550

Question

PASSAGEDirections Read the given passage carefully and find the answers of following questions. LCM of two numbers A and B is 60. B is a 2-digit number which leaves remainder as 2 when divided by 6. It is also given B>A.Read the instructions carefullyFind Maximum value of A+B.OPTIONS23323550

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Solution

To solve this problem, we need to follow these steps:

  1. Understand the given information:

    • The Least Common Multiple (LCM) of two numbers A A and B B is 60.
    • B B is a 2-digit number that leaves a remainder of 2 when divided by 6.
    • B B is greater than A A .
  2. Identify possible values for B B :

    • Since B B leaves a remainder of 2 when divided by 6, B B can be written as B=6k+2 B = 6k + 2 where k k is an integer.
    • B B is a 2-digit number, so 10B99 10 \leq B \leq 99 .
  3. List the possible values of B B :

    • We need to find values of B B that fit the form 6k+2 6k + 2 and are within the range of 10 to 99.
    • Possible values of B B are: 14, 20, 26, 32, 38, 44, 50, 56, 62, 68, 74, 80, 86, 92, 98.
  4. Determine the corresponding values of A A :

    • Since the LCM of A A and B B is 60, A A must be a factor of 60.
    • The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
  5. Check each possible B B to find the corresponding A A :

    • For each B B , we need to check if there is a factor A A such that the LCM of A A and B B is 60 and B>A B > A .
  6. Calculate the maximum value of A+B A + B :

    • We need to find the pair (A,B)(A, B) that satisfies the conditions and gives the maximum sum A+B A + B .

Let's go through the possible values of B B and find the corresponding A A :

  • For B=14 B = 14 :

    • The factors of 60 that are less than 14 are: 1, 2, 3, 4, 5, 6, 10, 12.
    • Check if the LCM of each factor with 14 is 60:
      • LCM(10, 14) = 70 (not 60)
      • LCM(12, 14) = 84 (not 60)
      • LCM(6, 14) = 42 (not 60)
      • LCM(5, 14) = 70 (not 60)
      • LCM(4, 14) = 28 (not 60)
      • LCM(3, 14) = 42 (not 60)
      • LCM(2, 14) = 14 (not 60)
      • LCM(1, 14) = 14 (not 60)
    • No valid A A for B=14 B = 14 .
  • For B=20 B = 20 :

    • The factors of 60 that are less than 20 are: 1, 2, 3, 4, 5, 6, 10, 12, 15.
    • Check if the LCM of each factor with 20 is 60:
      • LCM(15, 20) = 60 (valid pair)
    • A=15 A = 15 , B=20 B = 20 , A+B=35 A + B = 35 .
  • For B=26 B = 26 :

    • The factors of 60 that are less than 26 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20.
    • Check if the LCM of each factor with 26 is 60:
      • No valid A A for B=26 B = 26 .
  • Continue this process for other values of B B .

After checking all possible values, we find that the maximum value of A+B A + B is achieved with B=20 B = 20 and A=15 A = 15 , giving A+B=35 A + B = 35 .

Therefore, the maximum value of A+B A + B is 35.

Answer: 35

This problem has been solved

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