Two particles of equal mass m move in a circle of radius r under the action of their mutual gravitational attraction. The speed of each particle will be :Gm2r−−−√4Gmr−−−−√Gmr−−−√Gm4r−−−√

Two particles of equal mass go round a circle of radius under the action of their mutualgravitational attraction. The speed of each particle is

Two particles having mass 4 kg and 2 kg are moving in a circular path having radius 16cm and 4 cm. If their time period are same then the ratio of angular velocity will be

Two particles A and B, initially at rest, move to­wards each other under the mutual force of attraction. At the instant when the speed of A is v and the speed of B is 2v, the speed of the centre of mass of the system is

In free space on a circle with radius R0, four point masses m are located at the vertices of the inscribed square, two of them carry charge +q, and the other two charge −q. At the initial moment all these particles have same speed in clockwise direction as shown. It is known that during the motion the minimum distance from any of the point masses to the centre O of the initial circle is R1(R1<R0). Consider that at any time, the charges are at the vertices of square centered at point O. The action of gravitational forces can be neglected. Determine the speed (in m/s) of any particle at a position having a distance R1 from the centre of the circle. Take m=22√−1gm, q=1μC,R0=2R1=1 m

Two particles of massesm1 andm2 are placed at a distancer. The ratio of gravitational force on massm1 due tomassm2 and on massm2 due to massm1