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Given below are the standard enthalpies of formation of liquid hexene and oxygen gas included in this chemical equation,C6H12 (l) + 9O2 (g) → 6CO2 (g) + 6H2O (l).Compute for the enthalpy changes of reaction of the given chemical reaction and identify what kind of thermochemical reaction it is.

Question

Given below are the standard enthalpies of formation of liquid hexene and oxygen gas included in this chemical equation,C6H12 (l) + 9O2 (g) → 6CO2 (g) + 6H2O (l).Compute for the enthalpy changes of reaction of the given chemical reaction and identify what kind of thermochemical reaction it is.

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Solution 1

I'm sorry, but you didn't provide the standard enthalpies of formation for the substances involved in the reaction. The enthalpy change of the reaction (ΔH) can be calculated using the formula:

ΔH = Σ ΔHf (products) - Σ ΔHf (reactants)

where ΔHf is the standard enthalpy of formation of the substances.

Once we have the ΔH, we can determine the type of the reaction. If ΔH is negative, the reaction is exothermic (releases heat). If ΔH is positive, the reaction is endothermic (absorbs heat).

Please provide the standard enthalpies of formation for the substances involved in the reaction.

This problem has been solved

Solution 2

To solve this problem, we need to know the standard enthalpies of formation (∆Hf°) for all the substances involved in the reaction. The standard enthalpy of formation is the change in enthalpy when one mole of a substance in the standard state is formed from its pure elements under the same conditions.

The enthalpy change of the reaction (∆Hrxn) can be calculated using Hess's Law, which states that the change in enthalpy in a chemical reaction is the same whether the reaction takes place in one step or in a series of steps. In other words, enthalpy is a state function.

The formula to calculate ∆Hrxn is:

∆Hrxn = ∑ ∆Hf° (products) - ∑ ∆Hf° (reactants)

Where:

  • ∑ ∆Hf° (products) is the sum of the standard enthalpies of formation of the products, each multiplied by its stoichiometric coefficient in the balanced chemical equation.
  • ∑ ∆Hf° (reactants) is the sum of the standard enthalpies of formation of the reactants, each multiplied by its stoichiometric coefficient in the balanced chemical equation.

If ∆Hrxn is negative, the reaction is exothermic (releases heat). If ∆Hrxn is positive, the reaction is endothermic (absorbs heat).

Unfortunately, you didn't provide the standard enthalpies of formation for the substances involved in the reaction. If you provide them, I can help you calculate ∆Hrxn and determine whether the reaction is exothermic or endothermic.

This problem has been solved

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