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A thermochemical equation is an equation which shows the heat involved in the process (the heat released or absorbed when a reaction takes place). Give the thermochemical equation for the combustion of benzene below.C6H6 (l) + 7½ O2 (g) —> 3 H2O (l ) + 6 CO2 (g)                 ΔH = - 3269 kJ*3 pointsC6H6 (l) + 7 ½ O2 (g) —> 3 H2O (l ) + 6 CO2 (g) - 3269 kJC6H6 (l) + 7 ½ O2 (g) —> 3 H2O (l ) + 6 CO2 (g) + 3269 kJC6H6 (l) + 7 ½ O2 (g) - 3269 kJ —> 3 H2O (l ) + 6 CO2 (g)C6H6 (l) + 7 ½ O2 (g) + 3269 kJ —> 3 H2O (l ) + 6 CO2 (g)

Question

A thermochemical equation is an equation which shows the heat involved in the process (the heat released or absorbed when a reaction takes place). Give the thermochemical equation for the combustion of benzene below.C6H6 (l) + 7½ O2 (g) —> 3 H2O (l ) + 6 CO2 (g)                 ΔH = - 3269 kJ*3 pointsC6H6 (l) + 7 ½ O2 (g) —> 3 H2O (l ) + 6 CO2 (g) - 3269 kJC6H6 (l) + 7 ½ O2 (g) —> 3 H2O (l ) + 6 CO2 (g) + 3269 kJC6H6 (l) + 7 ½ O2 (g) - 3269 kJ —> 3 H2O (l ) + 6 CO2 (g)C6H6 (l) + 7 ½ O2 (g) + 3269 kJ —> 3 H2O (l ) + 6 CO2 (g)

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Solution

The correct thermochemical equation for the combustion of benzene is:

C6H6 (l) + 7 ½ O2 (g) —> 3 H2O (l ) + 6 CO2 (g) ΔH = - 3269 kJ

This equation indicates that the reaction is exothermic (releases heat) because the ΔH value is negative. The negative sign shows that energy is lost (in the form of heat) when benzene combusts in the presence of oxygen to form water and carbon dioxide. The magnitude of the ΔH value (3269 kJ) represents the amount of heat released when one mole of benzene undergoes combustion under standard conditions.

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At constant pressure, the combustion of 5.00 g of C2H6(g) releases 259 kJ of heat. What is ΔH for the reaction given below? 2 C2H6(g) + 7 O2(g)–> 4 CO2(g) + 6 H2O(l). Hint: Convert 5.0 grams to moles (divide by molar mass).  Divide 259 kJ by your answer to get kJ/mole reacted.  Next, multiply by 2 since there are 2 C2H6(g) in the balanced reaction. Group of answer choices1800 kJ3108 kJ5168 kJ2155 kJ

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