Brown hair (H) is dominant to blonde hair (h). Brown eyes (B) are dominant to blue eyes (b).Rebecca has blue eyes and is heterozygous for hair color. Her husband Thomas, has blue eyes and blonde hair.Using FOIL method, what are the possible gamete combinations?ResponsesRebecca = bH, Bh; Thomas = BhRebecca = bH, Bh; Thomas = BhRebecca = bH, bh; Thomas = bhRebecca = bH, bh; Thomas = bhRebecca = BH, bh; Thomas = bhRebecca = BH, bh; Thomas = bhRebecca = BH, bh; Thomas = Bh
Question
Brown hair (H) is dominant to blonde hair (h). Brown eyes (B) are dominant to blue eyes (b).Rebecca has blue eyes and is heterozygous for hair color. Her husband Thomas, has blue eyes and blonde hair.Using FOIL method, what are the possible gamete combinations?ResponsesRebecca = bH, Bh; Thomas = BhRebecca = bH, Bh; Thomas = BhRebecca = bH, bh; Thomas = bhRebecca = bH, bh; Thomas = bhRebecca = BH, bh; Thomas = bhRebecca = BH, bh; Thomas = bhRebecca = BH, bh; Thomas = Bh
Solution
The question is asking for the possible gamete combinations of Rebecca and Thomas using the FOIL method.
First, let's determine the genotypes of Rebecca and Thomas.
Rebecca has blue eyes and is heterozygous for hair color. Blue eyes are recessive, so her genotype for eyes is bb. Heterozygous for hair color means she has one dominant allele (H) and one recessive allele (h), so her genotype for hair is Hh.
Thomas has blue eyes and blonde hair. Both blue eyes and blonde hair are recessive traits, so his genotype for eyes is bb and for hair is hh.
Now, let's use the FOIL method to determine the possible gamete combinations. FOIL stands for First, Outer, Inner, Last. It's a method used in genetics to determine all possible combinations of alleles that can result from a cross.
For Rebecca, the possible combinations are: First: bH Outer: bh Inner: bH Last: bh
So, Rebecca's possible gamete combinations are bH and bh.
For Thomas, since both his alleles for each trait are the same (bb and hh), his only possible gamete combination is bh.
So, the correct answer is: Rebecca = bH, bh; Thomas = bh.
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