To solve this problem, you can follow these steps:

1. Read the size of the matrix (N, M) from the input.
2. Create an empty matrix of size N x M.
3. Loop over the range N (number of rows in the matrix) and for each iteration, read a line from the input, split it into M elements, convert each element to an integer and add it to the current row of the matrix.
4. Read the size of the array (A) from the input.
5. Read the array from the input, split it into A elements, convert each element to an integer and store it in a list.
6. Loop over each row in the matrix and for each row, loop over each element in the row. If the element is in the array, increment a counter. After checking all elements in the row, print the counter and reset it to 0 for the next row.

Here is a Python code that implements these steps:

```python
N, M = map(int, input().split())
matrix = [list(map(int, input().split())) for _ in range(N)]
A = int(input())
array = set(map(int, input().split()))

for row in matrix:
count = sum(1 for element in row if element in array)
print(count)
```

This code uses a set to store the array elements because checking if an element is in a set is faster than checking if it is in a list. The `sum` function with a generator expression is used to count the number of elements in each row that are in the array.

Question

To solve this problem, you can follow these steps:

1. Read the size of the matrix (N, M) from the input.
2. Create an empty matrix of size N x M.
3. Loop over the range N (number of rows in the matrix) and for each iteration, read a line from the input, split it into M elements, convert each element to an integer and add it to the current row of the matrix.
4. Read the size of the array (A) from the input.
5. Read the array from the input, split it into A elements, convert each element to an integer and store it in a list.
6. Loop over each row in the matrix and for each row, loop over each element in the row. If the element is in the array, increment a counter. After checking all elements in the row, print the counter and reset it to 0 for the next row.

Here is a Python code that implements these steps:

```python
N, M = map(int, input().split())
matrix = [list(map(int, input().split())) for _ in range(N)]
A = int(input())
array = set(map(int, input().split()))

for row in matrix:
    count = sum(1 for element in row if element in array)
    print(count)
```

This code uses a set to store the array elements because checking if an element is in a set is faster than checking if it is in a list. The `sum` function with a generator expression is used to count the number of elements in each row that are in the array.

Knowee AI · Accepted Answer

To solve this problem, you can follow these steps:

1. Read the size of the matrix (N, M) from the input.
2. Create an empty matrix of size N x M.
3. Loop over the range N (number of rows in the matrix) and for each iteration, read a line from the input, split it into M elements, convert each element to an integer and add it to the current row of the matrix.
4. Read the size of the array (A) from the input.
5. Read the array from the input, split it into A elements, convert each element to an integer and store it in a list.
6. Loop over each row in the matrix and for each row, loop over each element in the row. If the element is in the array, increment a counter. After checking all elements in the row, print the counter and reset it to 0 for the next row.

Here is a Python code that implements these steps:

```python
N, M = map(int, input().split())
matrix = [list(map(int, input().split())) for _ in range(N)]
A = int(input())
array = set(map(int, input().split()))

for row in matrix:
    count = sum(1 for element in row if element in array)
    print(count)
```

This code uses a set to store the array elements because checking if an element is in a set is faster than checking if it is in a list. The `sum` function with a generator expression is used to count the number of elements in each row that are in the array.

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