The output of this code will be:

1
2
3
4

Here's the step by step explanation:

1. The variable x is initially set to 1.
2. The program enters an infinite loop (while True).
3. Inside the loop, the program checks if x is divisible by 5 (x % 5 == 0). If it is, the loop breaks.
4. If x is not divisible by 5, the program prints the value of x and then increments x by 1 (x += 1).
5. This process repeats until x is divisible by 5. In this case, when x is 5, the loop breaks and the program ends.
6. So, the numbers 1, 2, 3, and 4 are printed before the loop breaks.

Question

The output of this code will be:

1
2
3
4

Here's the step by step explanation:

1. The variable x is initially set to 1.
2. The program enters an infinite loop (while True).
3. Inside the loop, the program checks if x is divisible by 5 (x % 5 == 0). If it is, the loop breaks.
4. If x is not divisible by 5, the program prints the value of x and then increments x by 1 (x += 1).
5. This process repeats until x is divisible by 5. In this case, when x is 5, the loop breaks and the program ends.
6. So, the numbers 1, 2, 3, and 4 are printed before the loop breaks.

Knowee AI · Accepted Answer

The output of this code will be:

1
2
3
4

Here's the step by step explanation:

1. The variable x is initially set to 1.
2. The program enters an infinite loop (while True).
3. Inside the loop, the program checks if x is divisible by 5 (x % 5 == 0). If it is, the loop breaks.
4. If x is not divisible by 5, the program prints the value of x and then increments x by 1 (x += 1).
5. This process repeats until x is divisible by 5. In this case, when x is 5, the loop breaks and the program ends.
6. So, the numbers 1, 2, 3, and 4 are printed before the loop breaks.

Study the following program: x = 1 while True: if x % 5 = = 0: break print(x) x + = 1What will be the output of this code?

Question

Solution

Similar Questions

Upgrade your grade with Knowee