The only force acting on a 5kg object has components Fx = 15N and Fy = 20N. the resultant acceleration is:
Question
The only force acting on a 5kg object has components Fx = 15N and Fy = 20N. the resultant acceleration is:
Solution 1
To find the resultant acceleration, we first need to find the resultant force.
Step 1: Find the resultant force The resultant force (F) can be found using Pythagoras' theorem since the components are at right angles to each other.
F = sqrt(Fx^2 + Fy^2) F = sqrt((15N)^2 + (20N)^2) F = sqrt(225 + 400) F = sqrt(625) F = 25N
Step 2: Find the acceleration Next, we use Newton's second law (F = ma) to find the acceleration (a).
a = F/m a = 25N / 5kg a = 5 m/s^2
So, the resultant acceleration of the object is 5 m/s^2.
Solution 2
First, we need to find the resultant force. The resultant force (F) can be found using the Pythagorean theorem since the two components of the force form a right triangle.
F = sqrt(Fx^2 + Fy^2) F = sqrt((15N)^2 + (20N)^2) F = sqrt(225N^2 + 400N^2) F = sqrt(625N^2) F = 25N
Next, we use Newton's second law of motion, F = ma, where F is the force, m is the mass, and a is the acceleration. We can rearrange the equation to solve for acceleration (a).
a = F/m a = 25N / 5kg a = 5 m/s^2
So, the resultant acceleration of the object is 5 m/s^2.
Similar Questions
A force of 20 N acts upon a 5 kg block. Calculate the acceleration of the object.
A 5kg object is to be given an upward acceleration of 3m/s2 by a rope pulling straight upward on it. The tension in the rope is (g = 10m/s2).
An object with a mass of 5 kg is accelerating at 2.5 m/s2. What is the net force on the object?
A body of 5kg is moving with a velocity of 20m/s. If a force of 100N is applied on it for 10sec in the same direction as its velocity, what will now be the velocity of body?
The acceleration that is produced by a 15N force in a mass of 8 kg will be equal toA.1.5 ms−2B.1.87 ms−2C.2.35 ms−2D.2 ms−2
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.