Knowee
Questions
Features
Study Tools

Obtain the derivative of ๐‘ง=(2๐‘ฅ-๐‘ฆ)(๐‘ฅ+3๐‘ฆ) with respect to yQuestion 10Answera.5๐‘ฅ-6๐‘ฆb.(2๐‘ฅ-1)(๐‘ฅ+3)c.4๐‘ฅ+5๐‘ฆd.(2-๐‘ฆ)(1+3๐‘ฆ)

Question

Obtain the derivative of ๐‘ง=(2๐‘ฅ-๐‘ฆ)(๐‘ฅ+3๐‘ฆ) with respect to yQuestion 10Answera.5๐‘ฅ-6๐‘ฆb.(2๐‘ฅ-1)(๐‘ฅ+3)c.4๐‘ฅ+5๐‘ฆd.(2-๐‘ฆ)(1+3๐‘ฆ)

๐Ÿง Not the exact question you are looking for?Go ask a question

Solution

Para obtener la derivada de z=(2xโˆ’y)(x+3y) z = (2x - y)(x + 3y) con respecto a y y , utilizamos la regla del producto. La regla del producto establece que si z=uโ‹…v z = u \cdot v , entonces dzdy=uโ‹…dvdy+vโ‹…dudy \frac{dz}{dy} = u \cdot \frac{dv}{dy} + v \cdot \frac{du}{dy} .

Primero, definimos: u=2xโˆ’y u = 2x - y v=x+3y v = x + 3y

Luego, calculamos las derivadas parciales de u u y v v con respecto a y y : dudy=โˆ’1 \frac{du}{dy} = -1 dvdy=3 \frac{dv}{dy} = 3

Aplicamos la regla del producto: dzdy=(2xโˆ’y)โ‹…3+(x+3y)โ‹…(โˆ’1) \frac{dz}{dy} = (2x - y) \cdot 3 + (x + 3y) \cdot (-1)

Simplificamos: dzdy=3(2xโˆ’y)โˆ’(x+3y) \frac{dz}{dy} = 3(2x - y) - (x + 3y) dzdy=6xโˆ’3yโˆ’xโˆ’3y \frac{dz}{dy} = 6x - 3y - x - 3y dzdy=5xโˆ’6y \frac{dz}{dy} = 5x - 6y

Por lo tanto, la respuesta correcta es: a. 5xโˆ’6y 5x - 6y

This problem has been solved

Similar Questions

If ๐‘ง=๐‘ ๐‘–๐‘›โก(3๐‘ฅ+2๐‘ฆ), find its derivative with respect to xQuestion 7Answera.๐‘๐‘œ๐‘ โก(3+2๐‘ฆ)b.3๐‘๐‘œ๐‘ โก(3๐‘ฅ+2๐‘ฆ)c.๐‘ ๐‘–๐‘›โก(3+2๐‘ฆ)d.3๐‘ ๐‘–๐‘›โก(3+2๐‘ฆ)

Obtain the derivative of ๐‘ง=(2๐‘ฅ-๐‘ฆ)(๐‘ฅ+3๐‘ฆ) with respect to y

Determine the derivative of ๐‘“ with respect to ๐‘ฅ from๐‘“๐‘ฅ,๐‘ฆ=๐‘ก๐‘Ž๐‘›โก(3๐‘ฅ+4๐‘ฆ)Question 6Answera.3sin2โก(3๐‘ฅ+4๐‘ฆ)b.3๐‘ก๐‘Ž๐‘›โก(3+4๐‘ฆ)c.๐‘๐‘œ๐‘กโก(3+4๐‘ฆ)d.3sec2โก(3๐‘ฅ+4๐‘ฆ)

Find the derivative of the following function.๐‘ฆ=2๐‘ฅโˆ’4โ€พโ€พโ€พโ€พโ€พโ€พโ€พโˆš4d๐‘ฆd๐‘ฅ=

Determine the derivative of ๐‘ฆ๐‘ฅ=๐‘ฅ2 at the point xQuestion 8Answera.2๐‘ฅb.๐‘ฅ2c.2d.2๐‘ฅ2

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.