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Question 9A calorimeter holds 50 g water at 29.0°C. A sample of hot iron is added to the water, and the final temperature of the water and iron is 22.0°C. What is the change in enthalpy associated with the change in the water’s temperature?Note: The specific heat of water is 4.18 .Show your work and circle your answer.PENCILTHINBLACK

Question

Question 9A calorimeter holds 50 g water at 29.0°C. A sample of hot iron is added to the water, and the final temperature of the water and iron is 22.0°C. What is the change in enthalpy associated with the change in the water’s temperature?Note: The specific heat of water is 4.18 .Show your work and circle your answer.PENCILTHINBLACK

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Solution

To find the change in enthalpy (ΔH) associated with the change in the water's temperature, we can use the formula:

ΔH = m * c * ΔT

where: m = mass of the water = 50 g c = specific heat of water = 4.18 J/g°C ΔT = change in temperature = final temperature - initial temperature = 22.0°C - 29.0°C = -7.0°C

Substituting these values into the formula, we get:

ΔH = 50 g * 4.18 J/g°C * -7.0°C = -1463 J

The negative sign indicates that heat is being lost by the water, which is expected since the water is cooling down.

So, the change in enthalpy associated with the change in the water's temperature is -1463 J.

This problem has been solved

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