60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and  Alloy B has tin and copper in the ration 1 : 4, then the amount of tin in the new alloy isOptions :36 kg44 kg53 kg80 kg

To solve this problem, we need to find out how much tin is in each alloy first, and then add those amounts together.

1. In alloy A, the ratio of lead to tin is 3:2. This means that for every 5 parts of the alloy, 2 parts are tin. So, the amount of tin in 60 kg of alloy A is (2/5)*60 = 24 kg.

2. In alloy B, the ratio of tin to copper is 1:4. This means that for every 5 parts of the alloy, 1 part is tin. So, the amount of tin in 100 kg of alloy B is (1/5)*100 = 20 kg.

3. Adding the amount of tin in alloys A and B gives us the total amount of tin in the new alloy: 24 kg + 20 kg = 44 kg.

So, the amount of tin in the new alloy is 44 kg.

To solve this problem, we need to find out how much tin is in each alloy first, and then add those amounts together.

1. In alloy A, the ratio of lead to tin is 3:2. This means that for every 5 parts of the alloy, 2 parts are tin. So, to find out how much tin is in 60 kg of alloy A, we calculate (2/5) * 60 = 24 kg.

2. In alloy B, the ratio of tin to copper is 1:4. This means that for every 5 parts of the alloy, 1 part is tin. So, to find out how much tin is in 100 kg of alloy B, we calculate (1/5) * 100 = 20 kg.

3. Finally, to find out how much tin is in the new alloy, we add the amount of tin in alloy A to the amount of tin in alloy B: 24 kg + 20 kg = 44 kg.

So, the amount of tin in the new alloy is 44 kg.