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largest and smallest element in Binary Search TreeGiven a binary search tree find the kth largest and smallest element in Binary Search Tree.Input :First line of input contains number of elements in an arraaySecond line of input contains an array of elementsThird line of input contains the value of 'K' Output : First line of output contains the largest element in an arraySecond line of output contains the smallest element in an array.

Question

largest and smallest element in Binary Search TreeGiven a binary search tree find the kth largest and smallest element in Binary Search Tree.Input :First line of input contains number of elements in an arraaySecond line of input contains an array of elementsThird line of input contains the value of 'K' Output : First line of output contains the largest element in an arraySecond line of output contains the smallest element in an array.

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Solution

The problem is asking to find the kth largest and smallest element in a Binary Search Tree (BST). Here is a step-by-step solution in Python:

  1. First, we need to create a BST from the given array. A BST is a tree in which for each node, value of all the nodes in left child is less and value of all the nodes in right child is more.
class Node:
    def __init__(self, key):
        self.left = None
        self.right = None
        self.val = key

def insert(root, key):
    if root is None:
        return Node(key)
    else:
        if root.val < key:
            root.right = insert(root.right, key)
        else:
            root.left = insert(root.left, key)
    return root
  1. To find the kth smallest element, we can do an in-order traversal of the BST. In-order traversal of BST retrieves elements in sorted order.
def kth_smallest(root, k):
    stack = []
    while True:
        while root:
            stack.append(root)
            root = root.left
        root = stack.pop()
        k -= 1
        if not k:
            return root.val
        root = root.right
  1. To find the kth largest element, we can do a reverse in-order traversal of the BST. Reverse in-order traversal of BST retrieves elements in descending order.
def kth_largest(root, k):
    stack = []
    while True:
        while root:
            stack.append(root)
            root = root.right
        root = stack.pop()
        k -= 1
        if not k:
            return root.val
        root = root.left
  1. Now, we can use these functions to find the kth smallest and largest elements.
n = int(input())
arr = list(map(int, input().split()))
k = int(input())

root = None
for element in arr:
    root = insert(root, element)

print(kth_largest(root, k))
print(kth_smallest(root, k))

This program first reads the number of elements, the elements themselves, and the value of 'k'. It then constructs the BST, and finally prints the kth largest and smallest elements.

This problem has been solved

Similar Questions

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