When chlorine is added to acetylene, 1,1,2,2-tetrachloroethance is formed:2Cl2 + C2H2 ⟶ C2H2Cl4How many liters of chlorine at STP will be needed to make 52.49 g of C2H2Cl4?

To solve this problem, we need to follow these steps:

1. First, we need to find the molar mass of C2H2Cl4. The molar mass of carbon (C) is approximately 12.01 g/mol, hydrogen (H) is approximately 1.01 g/mol, and chlorine (Cl) is approximately 35.45 g/mol. So, the molar mass of C2H2Cl4 is (212.01) + (21.01) + (4*35.45) = 24.02 + 2.02 + 141.8 = 167.84 g/mol.

2. Next, we need to find the number of moles of C2H2Cl4 in 52.49 g. We can do this by dividing the mass of the substance by its molar mass. So, 52.49 g / 167.84 g/mol = 0.313 moles of C2H2Cl4.

3. According to the balanced chemical equation, 2 moles of Cl2 are needed to produce 1 mole of C2H2Cl4. Therefore, we need 2 * 0.313 = 0.626 moles of Cl2 to produce 52.49 g of C2H2Cl4.

4. At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, 0.626 moles of Cl2 will occupy 0.626 * 22.4 = 14.02 liters.

So, 14.02 liters of chlorine at STP will be needed to make 52.49 g of C2H2Cl4.