The first step is to find a number that leaves a remainder of 3 when divided by 4, 5, 6, and 7. This number is the least common multiple (LCM) of 4, 5, 6, and 7, plus 3.

The LCM of 4, 5, 6, and 7 is 420. Adding 3 to this gives 423.

Next, we need to find a four-digit number that is a multiple of 423 and lies between 3600 and 3800.

The smallest four-digit multiple of 423 is 4230, which is too large. So, we need to find a multiple of 423 that is less than 3600 and add 423 to it until we get a number between 3600 and 3800.

The largest multiple of 423 that is less than 3600 is 3384 (which is 423 * 8). Adding 423 to this gives 3807, which is too large.

So, there is no four-digit number that leaves a remainder of 3 when divided by 4, 5, 6, and 7 and lies between 3600 and 3800.

Therefore, none of the options are correct.

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The first step is to find a number that leaves a remainder of 3 when divided by 4, 5, 6, and 7. This number is the least common multiple (LCM) of 4, 5, 6, and 7, plus 3.

The LCM of 4, 5, 6, and 7 is 420. Adding 3 to this gives 423.

Next, we need to find a four-digit number that is a multiple of 423 and lies between 3600 and 3800.

The smallest four-digit multiple of 423 is 4230, which is too large. So, we need to find a multiple of 423 that is less than 3600 and add 423 to it until we get a number between 3600 and 3800.

The largest multiple of 423 that is less than 3600 is 3384 (which is 423 * 8). Adding 423 to this gives 3807, which is too large.

So, there is no four-digit number that leaves a remainder of 3 when divided by 4, 5, 6, and 7 and lies between 3600 and 3800.

Therefore, none of the options are correct.

Knowee AI · Accepted Answer

The first step is to find a number that leaves a remainder of 3 when divided by 4, 5, 6, and 7. This number is the least common multiple (LCM) of 4, 5, 6, and 7, plus 3.

The LCM of 4, 5, 6, and 7 is 420. Adding 3 to this gives 423.

Next, we need to find a four-digit number that is a multiple of 423 and lies between 3600 and 3800.

The smallest four-digit multiple of 423 is 4230, which is too large. So, we need to find a multiple of 423 that is less than 3600 and add 423 to it until we get a number between 3600 and 3800.

The largest multiple of 423 that is less than 3600 is 3384 (which is 423 * 8). Adding 423 to this gives 3807, which is too large.

So, there is no four-digit number that leaves a remainder of 3 when divided by 4, 5, 6, and 7 and lies between 3600 and 3800.

Therefore, none of the options are correct.

Let ‘x’ be the four digit number which when divided by 4, 5, 6 and 7 leaves a remainder of 3 in each case. If ‘x’ lies between 3600 and 3800, then what is the sum of digits of ‘x’?OPTIONS 21 19 20 23

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