The pressure of the gas in a constant volume gas thermometer is 120 cm of mercury when placed inmelting ice at 1 atm. When the bulb is placed in a liquid, the pressure becomes 200 cm of mercury.Find the temperature of the liquid. (Given0 C = 273 K

To find the temperature of the liquid, we can use the relationship between pressure and temperature in a constant volume gas thermometer.

First, let's convert the pressure values from cm of mercury to atm. Since 1 atm is equal to 76 cm of mercury, the initial pressure of 120 cm of mercury is equivalent to 120/76 = 1.58 atm. Similarly, the final pressure of 200 cm of mercury is equivalent to 200/76 = 2.63 atm.

Next, we can use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since the volume is constant in this case, we can rewrite the equation as P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.

Plugging in the values, we have 1.58/T1 = 2.63/T2.

Now, let's convert the temperature from Celsius to Kelvin. We are given that 0°C is equal to 273 K. So, the temperature of the melting ice is 273 K.

Substituting the values, we have 1.58/273 = 2.63/T2.

Simplifying the equation, we get T2 = (2.63 * 273) / 1.58.

Calculating this, we find that T2 is approximately 454.24 K.

Therefore, the temperature of the liquid is approximately 454.24 K.