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If ๐‘Ž2 + ๐‘2 + ๐‘2 = 1 and 2(๐‘Ž๐‘ + ๐‘๐‘ + ๐‘๐‘Ž) = 80, then the value of(๐‘Ž + ๐‘ + ๐‘)2 is

Question

If ๐‘Ž2 + ๐‘2 + ๐‘2 = 1 and 2(๐‘Ž๐‘ + ๐‘๐‘ + ๐‘๐‘Ž) = 80, then the value of(๐‘Ž + ๐‘ + ๐‘)2 is

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Solution

The expression (a + b + c)^2 can be expanded to a^2 + b^2 + c^2 + 2(ab + bc + ca).

From the given conditions, we know that a^2 + b^2 + c^2 = 1 and 2(ab + bc + ca) = 80.

Substituting these values into the expanded expression, we get 1 + 80 = 81.

So, the value of (a + b + c)^2 is 81.

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If ๐‘Ž2 + ๐‘2 + ๐‘2 = 1 and 2(๐‘Ž๐‘ + ๐‘๐‘ + ๐‘๐‘Ž) = 80, then the value of(๐‘Ž + ๐‘ + ๐‘)2 is

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Given the equation which expression also equals 80?

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