A toy car travels on a circular track at a constant speed of 0.50 m s –1. It passes a point on thetrack at time t = 0 and takes a time of 40 s to travel once around the track.The magnitude of the average velocity of the car between t = 0 and t = 20 s is v20.The magnitude of the average velocity of the car between t = 0 and t = 40 s is v40.What are v20 and v40?

The average velocity of an object moving in a circular path is given by the total displacement divided by the total time taken.

1. For v20: The toy car is moving in a circular path and it takes 40 seconds to complete one full circle. So, in 20 seconds, it would have covered half the circle. But since it's a circular path, the displacement at half the circle is the diameter of the circle. However, since we are asked for the magnitude of the average velocity, and not the vector, we only consider the distance travelled, not the displacement. In 20 seconds, the car travels half the circumference of the circle. The speed of the car is 0.50 m/s, so in 20 seconds, it travels 0.50 m/s * 20 s = 10 meters. Therefore, v20 = total distance / total time = 10 m / 20 s = 0.50 m/s.

2. For v40: In 40 seconds, the car completes one full circle and comes back to the starting point. In a circular path, the displacement after one full circle is zero because the initial and final positions are the same. Therefore, the average velocity v40 = total displacement / total time = 0 m / 40 s = 0 m/s.