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The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration a is 3 : 2. The value of a is  n3g.𝑛3𝑔. Value of n, is (g : Acceleration due to gravity of the earth)Single-digit integer (-9 to 9)1234567890-.PreviousClearMark for Review & NextNextInstructionsEnglishNot VisitedNot AnsweredAnsweredMarked for ReviewAnswered & Marked for review(will be considered for evaluation)PHYSICSSection-ISection-II21222324252627282930

Question

The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration a is 3 : 2. The value of a is  n3g.𝑛3𝑔. Value of n, is (g : Acceleration due to gravity of the earth)Single-digit integer (-9 to 9)1234567890-.PreviousClearMark for Review & NextNextInstructionsEnglishNot VisitedNot AnsweredAnsweredMarked for ReviewAnswered & Marked for review(will be considered for evaluation)PHYSICSSection-ISection-II21222324252627282930

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Solution

The given ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration a is 3 : 2.

Let's denote the weight of the man in the stationary lift as W1 and the weight of the man when the lift is moving downward as W2.

We know that weight is the product of mass and gravity, so we can write:

W1 = m*g (1)

When the lift is moving downward with acceleration a, the effective gravity becomes (g-a). So, the weight of the man becomes:

W2 = m*(g-a) (2)

Given that W1/W2 = 3/2, we can substitute equations (1) and (2) into this ratio:

(mg) / (m(g-a)) = 3/2

Solving for a, we get:

2g = 3g - 3a

3a = g

a = g/3

The question states that a = n3g, so we can equate this to our found value for a:

g/3 = n3g

Solving for n, we get:

n = 1/3

So, the value of n is 1/3. However, the question asks for a single-digit integer. Since 1/3 is not a single-digit integer, it seems there might be a mistake in the question or in the given options.

This problem has been solved

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