A body is projected with velocity  u  at an angle  θ  with the horizontal. The body makes  30∘  with the horizontal at  t  =  2  second and then after 1 second it reaches the maximum height. Then

A projectile is projected at 30∘ from horizontal with initial velocity 40 ms−1. The velocity of the projectile at t=2 s from the start will be: (Given g=10 m/s2 )

An object is thrown vertically upwards with an initial velocity of m/s. (take g=10m/s2 Find –(innotebook)-(i) time taken to reach maximum height(ii) maximum height reached(iii) velocity after 5 seconds

A ball is projected straight upwards with an initial velocity of 20 m/s. It will reach its maximum height in approximately Question 19Answera.2.5sb.1.02sc.3.06sd.2.04se.1.5s

A particle of mass  m is projected with a speed  u from the ground at an angle  θ  =  π/3 with respect to horizontal (x-axis). When it has reached its maximum height, it collides completely inelastically with another particle of the same mass and velocity uî. The horizontal distance covered by the combined mass before reaching the ground is:

A body is so projected in the air that the horizontal range covered by the body is equal to the maximum vertical height attained by by the body during the motion. Find the angle of projection.