To find the least number which when doubled becomes exactly divisible by 9, 15, 21, and 30, we need to find the least common multiple (LCM) of these numbers.

Step 1: Prime factorization of each number
9 = 3^2
15 = 3 * 5
21 = 3 * 7
30 = 2 * 3 * 5

Step 2: Find the LCM
The LCM is the product of the highest power of all prime numbers in the factorization.
So, LCM = 2^1 * 3^2 * 5^1 * 7^1 = 630

But we need to find the number which when doubled is divisible by the LCM. So, the required number is 630/2 = 315.

So, the answer is D] 315.

Question

To find the least number which when doubled becomes exactly divisible by 9, 15, 21, and 30, we need to find the least common multiple (LCM) of these numbers.

Step 1: Prime factorization of each number
9 = 3^2
15 = 3 * 5
21 = 3 * 7
30 = 2 * 3 * 5

Step 2: Find the LCM
The LCM is the product of the highest power of all prime numbers in the factorization. 
So, LCM = 2^1 * 3^2 * 5^1 * 7^1 = 630

But we need to find the number which when doubled is divisible by the LCM. So, the required number is 630/2 = 315.

So, the answer is D] 315.

Knowee AI · Accepted Answer

To find the least number which when doubled becomes exactly divisible by 9, 15, 21, and 30, we need to find the least common multiple (LCM) of these numbers.

Step 1: Prime factorization of each number
9 = 3^2
15 = 3 * 5
21 = 3 * 7
30 = 2 * 3 * 5

Step 2: Find the LCM
The LCM is the product of the highest power of all prime numbers in the factorization. 
So, LCM = 2^1 * 3^2 * 5^1 * 7^1 = 630

But we need to find the number which when doubled is divisible by the LCM. So, the required number is 630/2 = 315.

So, the answer is D] 315.

What will be the least number which when doubled becomes exactly divisible by 9, 15, 21, and 30?Options :A] 196B] 189C] 630D] 315

Question

Solution

Similar Questions

Upgrade your grade with Knowee