To insert three arithmetic means between 4 and 16, we first need to find the common difference (d). The formula for the common difference in an arithmetic sequence is d = (b - a) / (n + 1), where a and b are the first and last terms, and n is the number of means.

Here, a = 4, b = 16, and n = 3.

So, d = (16 - 4) / (3 + 1) = 12 / 4 = 3.

The arithmetic means are then a + d, a + 2d, and a + 3d.

So, the three arithmetic means are 4 + 3 = 7, 4 + 2*3 = 10, and 4 + 3*3 = 13.

Therefore, the largest of the means is 13.

So, the answer is c. 13.

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To insert three arithmetic means between 4 and 16, we first need to find the common difference (d). The formula for the common difference in an arithmetic sequence is d = (b - a) / (n + 1), where a and b are the first and last terms, and n is the number of means.

Here, a = 4, b = 16, and n = 3.

So, d = (16 - 4) / (3 + 1) = 12 / 4 = 3.

The arithmetic means are then a + d, a + 2d, and a + 3d.

So, the three arithmetic means are 4 + 3 = 7, 4 + 2*3 = 10, and 4 + 3*3 = 13.

Therefore, the largest of the means is 13.

So, the answer is c. 13.

Knowee AI · Accepted Answer

To insert three arithmetic means between 4 and 16, we first need to find the common difference (d). The formula for the common difference in an arithmetic sequence is d = (b - a) / (n + 1), where a and b are the first and last terms, and n is the number of means.

Here, a = 4, b = 16, and n = 3.

So, d = (16 - 4) / (3 + 1) = 12 / 4 = 3.

The arithmetic means are then a + d, a + 2d, and a + 3d.

So, the three arithmetic means are 4 + 3 = 7, 4 + 2*3 = 10, and 4 + 3*3 = 13.

Therefore, the largest of the means is 13.

So, the answer is c. 13.

Insert three arithmetic means between 4 and 16. What is the largest of the means?Select one:a. 7b. 10c. 13d. 16

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