The isomeric alcohols with the formula C4H9OH that will produce an alkene that has cis and trans isomers, on treatment with conc. H2SO4 are 2-butanol and 2-methyl-2-propanol.

Step 1: Identify the isomers of C4H9OH. They are 1-butanol, 2-butanol, 2-methyl-1-propanol, and 2-methyl-2-propanol.

Step 2: Determine which of these isomers can form an alkene with cis and trans isomers. Only 2-butanol and 2-methyl-2-propanol can form such an alkene.

Step 3: Count the number of isomers that can form an alkene with cis and trans isomers. The answer is 2.

So, the answer is B 2.

Question

The isomeric alcohols with the formula C4H9OH that will produce an alkene that has cis and trans isomers, on treatment with conc. H2SO4 are 2-butanol and 2-methyl-2-propanol.

Step 1: Identify the isomers of C4H9OH. They are 1-butanol, 2-butanol, 2-methyl-1-propanol, and 2-methyl-2-propanol.

Step 2: Determine which of these isomers can form an alkene with cis and trans isomers. Only 2-butanol and 2-methyl-2-propanol can form such an alkene.

Step 3: Count the number of isomers that can form an alkene with cis and trans isomers. The answer is 2.

So, the answer is B 2.

Knowee AI · Accepted Answer

The isomeric alcohols with the formula C4H9OH that will produce an alkene that has cis and trans isomers, on treatment with conc. H2SO4 are 2-butanol and 2-methyl-2-propanol.

Step 1: Identify the isomers of C4H9OH. They are 1-butanol, 2-butanol, 2-methyl-1-propanol, and 2-methyl-2-propanol.

Step 2: Determine which of these isomers can form an alkene with cis and trans isomers. Only 2-butanol and 2-methyl-2-propanol can form such an alkene.

Step 3: Count the number of isomers that can form an alkene with cis and trans isomers. The answer is 2.

So, the answer is B 2.

Q9 How many of the isomeric alcohols with the formula C4H9OH will produce an alkene that has cis and trans isomers, on treatment with conc. H2SO4? A 1 B 2 C 3 D 4

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