Character arraysWhat is the output of this C code?#include<stdio.h>void main() { char str[] = "Code\0Tantra\0India"; printf("%s\n", str);}OptionsCode\0Tantra\0IndiaCodeCompilation errorCode Tantra India

The output of the given C code will be "Code".

Here's the step by step explanation:

1. The given C code declares a character array str[] and initializes it with the string "Code\0Tantra\0India".

2. In C, strings are actually one-dimensional array of characters terminated by a null character '\0'. So the '\0' character is used to mark the end of a string.

3. When the printf function is called with "%s\n" as the format specifier and str as the argument, it starts printing the characters from the beginning of the str array and stops when it encounters the first '\0' character.

4. Therefore, only "Code" is printed and the rest of the string after the first '\0' character is ignored.

So, the correct option is "Code".