Which is the prime factorization of 540? 22×33×522×33×5 45×2×545×2×5 2×3×9×102×3×9×10 6×9×10

The prime factorization of 540 is 2^2 x 3^3 x 5. This means that 540 can be written as the product of these prime numbers. Here's how you can find it:

1. Start by dividing 540 by the smallest prime number, which is 2. 540 divided by 2 is 270.
2. Continue dividing by 2 until you can't anymore. 270 divided by 2 is 135.
3. Now, move on to the next prime number, which is 3. 135 divided by 3 is 45.
4. Continue dividing by 3 until you can't anymore. 45 divided by 3 is 15, and 15 divided by 3 is 5.
5. The next prime number after 3 is 5, and 5 divided by 5 is 1. Once you reach 1, you've found all the prime factors.

So, the prime factorization of 540 is 2^2 x 3^3 x 5.