If ‘A’ is the L.C.M of 3, 5, 7, 9 and ‘B’ is the L.C.M of 4, 6, 8, 10 and ‘L’ is L.C.M of ‘A’ and ‘B’ then which of the following is true?L = 8B   L = 21BL = 62BL = 16B

To solve this problem, we first need to find the LCM of the given sets of numbers.

1. Find LCM of 3, 5, 7, 9: The LCM of 3, 5, 7, 9 is 315. This is because 315 is the smallest number that is a multiple of all these numbers.

2. Find LCM of 4, 6, 8, 10: The LCM of 4, 6, 8, 10 is 120. This is because 120 is the smallest number that is a multiple of all these numbers.

3. Find LCM of A and B: Now, we need to find the LCM of 315 (A) and 120 (B). The LCM of 315 and 120 is 2520. This is because 2520 is the smallest number that is a multiple of both 315 and 120.

Now, we need to check which of the given options is true.

1. L = 8B: If we substitute B = 120 into this equation, we get L = 8 * 120 = 960. This is not equal to the LCM we found (2520), so this option is not true.

2. L = 21B: If we substitute B = 120 into this equation, we get L = 21 * 120 = 2520. This is equal to the LCM we found, so this option is true.

3. L = 62B: If we substitute B = 120 into this equation, we get L = 62 * 120 = 7440. This is not equal to the LCM we found (2520), so this option is not true.

4. L = 16B: If we substitute B = 120 into this equation, we get L = 16 * 120 = 1920. This is not equal to the LCM we found (2520), so this option is not true.

So, the correct answer is L = 21B.