3.If (x + 1)2 + 1(x + 1)(x + 2) − (x − 1) = 0 . Then the value of 4x2 + 8x + 9
Question
3.If (x + 1)2 + 1(x + 1)(x + 2) − (x − 1) = 0 . Then the value of 4x2 + 8x + 9
Solution
The given equation is (x + 1)^2 + 1(x + 1)(x + 2) - (x - 1) = 0.
Let's simplify this equation step by step:
Step 1: Expand the terms = x^2 + 2x + 1 + x^2 + 3x + 2 - x + 1 = 0 = 2x^2 + 4x + 4 = 0
Step 2: Divide the entire equation by 2 to simplify = x^2 + 2x + 2 = 0
This is the simplified form of the given equation.
Now, we need to find the value of 4x^2 + 8x + 9.
Since we know that x^2 + 2x + 2 = 0, we can multiply the entire equation by 4 to get an equation in the form of 4x^2 + 8x + 8 = 0.
But we need to find the value of 4x^2 + 8x + 9.
Since 4x^2 + 8x + 8 = 0, adding 1 to both sides of the equation gives us 4x^2 + 8x + 9 = 1.
So, the value of 4x^2 + 8x + 9 is 1.
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