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A fraction has the denominator greater than its numerator by 6. But if you add 8 to the denominator, the value of the fraction would then become 1/3.  the fraction is :A.6/11B.6/13C.7/13D. NONE OF THESE

Question

A fraction has the denominator greater than its numerator by 6. But if you add 8 to the denominator, the value of the fraction would then become 1/3.  the fraction is :A.6/11B.6/13C.7/13D. NONE OF THESE

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Solution

To solve this problem, let's break it down step by step:

  1. Let's assume the numerator of the fraction is "x".
  2. According to the given information, the denominator is greater than the numerator by 6. So, the denominator can be represented as "x + 6".
  3. If we add 8 to the denominator, it becomes "x + 6 + 8", which simplifies to "x + 14".
  4. The new fraction, after adding 8 to the denominator, is equal to 1/3. So, we can set up the equation: x / (x + 14) = 1/3.
  5. To solve this equation, we can cross-multiply: 3x = x + 14.
  6. Simplifying further, we get: 2x = 14.
  7. Dividing both sides by 2, we find: x = 7.
  8. Now that we have the value of the numerator, we can substitute it back into the original fraction. The numerator is 7 and the denominator is 7 + 6 = 13.
  9. Therefore, the fraction is 7/13.

So, the correct answer is C. 7/13.

This problem has been solved

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