A 1000W heater is placed in an insulated beaker containing 750g of water at 100 ∘ C. The water vapour is allowed to escape. Assume that there is no loss to the surroundings via conduction, convection or radiation. The specific latent heat of vaporisation of water is 2260kJ/kg.Part AWater leftAll questions in this part are answered incorrectlyHow much water is left after 5.0minutes?
Question
A 1000W heater is placed in an insulated beaker containing 750g of water at 100 ∘ C. The water vapour is allowed to escape. Assume that there is no loss to the surroundings via conduction, convection or radiation. The specific latent heat of vaporisation of water is 2260kJ/kg.Part AWater leftAll questions in this part are answered incorrectlyHow much water is left after 5.0minutes?
Solution
First, we need to calculate the total energy supplied by the heater in 5 minutes.
The power of the heater is 1000W, which is equivalent to 1000 Joules per second.
So, in 5 minutes (or 300 seconds), the total energy supplied by the heater is:
1000 Joules/second * 300 seconds = 300,000 Joules
Next, we need to calculate how much water can be vaporised by this amount of energy.
The specific latent heat of vaporisation of water is 2260 kJ/kg, which is equivalent to 2,260,000 Joules/kg.
So, the mass of water that can be vaporised by 300,000 Joules is:
300,000 Joules / 2,260,000 Joules/kg = 0.133 kg
Finally, we need to subtract this mass from the initial mass of the water to find out how much water is left.
The initial mass of the water is 750g, which is equivalent to 0.75 kg.
So, the mass of water left after 5 minutes is:
0.75 kg - 0.133 kg = 0.617 kg
Therefore, after 5 minutes, there is 0.617 kg (or 617g) of water left in the beaker.
Similar Questions
A glass containing 50 g of water is left on a table in a room. After some time, only 10 g of the water remained. The specific latent heat of vaporization of water is 2.3 x 106 J kg-1. Determine the energy lost by the water in the glass due to evaporation.
A student measures 250g of water and pours it into a beaker. They heat the water over a Bunsen burner for five minutes, then measure the mass of the water again; this time it is 200g. The specific latent heat of vaporisation of water is 2260kJ/kg.How much energy has been transferred in evaporating the water?
The heat of vaporization of water at 100°C is 40.66 kJ/mol. Calculate the quantity of heat that is released when 5.00 g of steam condenses to liquid water at 100°C. Hint: Convert 5.0 grams of water to moles (divide by the molar mass of H2O), multiply answer by the heat of vaporization.
The latent heat of vaporisation of water is 2.26 x 105 J kg-1 22.6 x 105 J kg-1 22.6 x 106 J kg-1 6.22 x 105 J kg-1
Q1. 100g of water that is already at its boiling point, is boiled without any temperature change occurring. If the latent heat of vaporisation of water is 2260000J/kg, how much energy is needed to boil the water completely away?
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