A neutron is absorbed by a nucleus of uranium-235(23592U)U92235. One possible outcome is the production of two nuclides, barium-144(14456Ba)Ba56144 and krypton-89(8936Kr)Kr3689.How many neutrons are released in this reaction?
Question
A neutron is absorbed by a nucleus of uranium-235(23592U)U92235. One possible outcome is the production of two nuclides, barium-144(14456Ba)Ba56144 and krypton-89(8936Kr)Kr3689.How many neutrons are released in this reaction?
Solution
To solve this problem, we need to understand the law of conservation of mass number and atomic number in nuclear reactions.
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The mass number (A) is the sum of the number of protons and neutrons in the nucleus. For uranium-235, the mass number is 235. For barium-144, the mass number is 144, and for krypton-89, the mass number is 89.
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The atomic number (Z) is the number of protons in the nucleus. For uranium-235, the atomic number is 92. For barium-144, the atomic number is 56, and for krypton-89, the atomic number is 36.
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In a nuclear reaction, the total mass number and the total atomic number before the reaction must be equal to the total mass number and the total atomic number after the reaction.
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Before the reaction, the mass number is 235 (from uranium-235) plus 1 (from the neutron), which equals 236. The atomic number is 92 (from uranium-235).
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After the reaction, the total mass number is 144 (from barium-144) plus 89 (from krypton-89) plus the number of neutrons produced. The total atomic number is 56 (from barium-144) plus 36 (from krypton-89).
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By setting the total mass number before the reaction equal to the total mass number after the reaction, we can solve for the number of neutrons produced:
236 = 144 + 89 + number of neutrons number of neutrons = 236 - 144 - 89 = 3
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By setting the total atomic number before the reaction equal to the total atomic number after the reaction, we can check our answer:
92 = 56 + 36 92 = 92
So, the number of neutrons released in this reaction is 3.
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