A 285. mL solution was made by mixing 274. mL of hexane, which has a density of 0.66 /gmL, and 17.2 mL of toluene, which has a density of 0.87 /gmL.Calculate the volume percent of hexane in this solution.Be sure your answer has the right number of significant digits.
Question
A 285. mL solution was made by mixing 274. mL of hexane, which has a density of 0.66 /gmL, and 17.2 mL of toluene, which has a density of 0.87 /gmL.Calculate the volume percent of hexane in this solution.Be sure your answer has the right number of significant digits.
Solution
Step 1: Calculate the mass of each component.
For hexane: Mass = Volume x Density Mass = 274 mL x 0.66 g/mL = 180.84 g
For toluene: Mass = Volume x Density Mass = 17.2 mL x 0.87 g/mL = 14.964 g
Step 2: Calculate the total mass of the solution.
Total mass = Mass of hexane + Mass of toluene Total mass = 180.84 g + 14.964 g = 195.804 g
Step 3: Calculate the volume percent of hexane.
Volume percent = (Volume of hexane / Total volume) x 100% Volume percent = (274 mL / 285 mL) x 100% = 96.14%
So, the volume percent of hexane in the solution is 96.14%. This answer has 4 significant digits, which is appropriate given the number of significant digits in the original measurements.
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