A 1.04 L solution was made by mixing 116. mL of acetone, which has a density of 0.78 /gmL, and 0.89 L of toluene, which has a density of 0.87 /gmL.Calculate the volume percent of acetone in this solution.Be sure your answer has the right number of significant digits.
Question
A 1.04 L solution was made by mixing 116. mL of acetone, which has a density of 0.78 /gmL, and 0.89 L of toluene, which has a density of 0.87 /gmL.Calculate the volume percent of acetone in this solution.Be sure your answer has the right number of significant digits.
Solution
To calculate the volume percent of acetone in the solution, we need to follow these steps:
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First, we need to convert the volumes of acetone and toluene to the same units. In this case, we'll convert everything to milliliters (mL) for simplicity. We know that 1 L = 1000 mL, so 0.89 L of toluene is 890 mL.
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Now, we add the volumes of acetone and toluene to get the total volume of the solution. This is 116 mL (acetone) + 890 mL (toluene) = 1006 mL.
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Next, we calculate the volume percent of acetone. The formula for volume percent is (volume of solute / total volume) * 100. In this case, the solute is acetone. So, we have (116 mL / 1006 mL) * 100 = 11.53%.
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Finally, we need to consider significant digits. All of our given values have three significant digits, so our final answer should as well. Therefore, we round 11.53% to 11.5%.
So, the volume percent of acetone in the solution is 11.5%.
Similar Questions
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