What will be the number of passes to sort the elements using insertion sort?14, 12,16, 6, 3, 10

Insertion sort works by comparing each element in the list with the element next to it, starting from the second element. If the current element is smaller than the previous one, it swaps places with the previous element. This process continues until the entire list is sorted.

Here's a step-by-step breakdown of how insertion sort would sort the list [14, 12, 16, 6, 3, 10]:

1. Pass 1: Compare 14 and 12. 12 is smaller, so swap them. The list is now [12, 14, 16, 6, 3, 10].
2. Pass 2: Compare 14 and 16. 16 is larger, so no swap is needed. The list remains [12, 14, 16, 6, 3, 10].
3. Pass 3: Compare 16 and 6. 6 is smaller, so swap them. The list is now [12, 14, 6, 16, 3, 10]. Then compare 14 and 6. 6 is smaller, so swap them. The list is now [12, 6, 14, 16, 3, 10]. Finally, compare 12 and 6. 6 is smaller, so swap them. The list is now [6, 12, 14, 16, 3, 10].
4. Pass 4: Compare 16 and 3. 3 is smaller, so swap them. The list is now [6, 12, 14, 3, 16, 10]. Repeat this process for 14, 12, and 6. The list is now [3, 6, 12, 14, 16, 10].
5. Pass 5: Compare 16 and 10. 10 is smaller, so swap them. The list is now [3, 6, 12, 14, 10, 16]. Repeat this process for 14, 12, and 6. The list is now [3, 6, 10, 12, 14, 16].

So, it took 5 passes to sort the list using insertion sort.

Insertion sort works by comparing each element in the list with the element next to it, and swapping them if required. The number of passes required to sort the list will be equal to the number of elements in the list minus one.

Here are the steps for sorting the list [14, 12, 16, 6, 3, 10] using insertion sort:

1. Pass 1: Compare 14 and 12. Since 14 > 12, swap them. The list becomes [12, 14, 16, 6, 3, 10].
2. Pass 2: Compare 14 and 16. Since 14 < 16, no swap is needed. The list remains [12, 14, 16, 6, 3, 10].
3. Pass 3: Compare 16 and 6. Since 16 > 6, swap them. The list becomes [12, 14, 6, 16, 3, 10]. Now, compare 14 and 6. Since 14 > 6, swap them. The list becomes [12, 6, 14, 16, 3, 10]. Finally, compare 12 and 6. Since 12 > 6, swap them. The list becomes [6, 12, 14, 16, 3, 10].
4. Pass 4: Compare 16 and 3. Since 16 > 3, swap them. The list becomes [6, 12, 14, 3, 16, 10]. Repeat this process for 14, 12, and 6. The list becomes [3, 6, 12, 14, 16, 10].
5. Pass 5: Compare 16 and 10. Since 16 > 10, swap them. The list becomes [3, 6, 12, 14, 10, 16]. Repeat this process for 14, 12, and 6. The list becomes [3, 6, 10, 12, 14, 16].

So, it took 5 passes to sort the list using insertion sort.