The number of passes to sort the given numbers using insertion sort will be 5.

Here's the step-by-step process:

1. Pass 1: Compare 14 and 12. Since 12 is smaller, swap them. The list becomes 12, 14, 16, 6, 3, 10.
2. Pass 2: Compare 14 and 16. They are already in order. Then compare 16 and 6. Since 6 is smaller, move 16 to the right and insert 6 before 14. The list becomes 12, 6, 14, 16, 3, 10.
3. Pass 3: Compare 12 and 6. Since 6 is smaller, move 12 to the right and insert 6 at the beginning. Then compare 16 and 3. Since 3 is smaller, move 16, 14, and 12 to the right and insert 3 at the beginning. The list becomes 3, 6, 12, 14, 16, 10.
4. Pass 4: Compare 16 and 10. Since 10 is smaller, move 16 to the right and insert 10 before 14. The list becomes 3, 6, 10, 12, 14, 16.
5. Pass 5: All elements are already in order, so no more passes are needed.

So, the correct answer is 5.

Question

The number of passes to sort the given numbers using insertion sort will be 5.

Here's the step-by-step process:

1. Pass 1: Compare 14 and 12. Since 12 is smaller, swap them. The list becomes 12, 14, 16, 6, 3, 10.
2. Pass 2: Compare 14 and 16. They are already in order. Then compare 16 and 6. Since 6 is smaller, move 16 to the right and insert 6 before 14. The list becomes 12, 6, 14, 16, 3, 10.
3. Pass 3: Compare 12 and 6. Since 6 is smaller, move 12 to the right and insert 6 at the beginning. Then compare 16 and 3. Since 3 is smaller, move 16, 14, and 12 to the right and insert 3 at the beginning. The list becomes 3, 6, 12, 14, 16, 10.
4. Pass 4: Compare 16 and 10. Since 10 is smaller, move 16 to the right and insert 10 before 14. The list becomes 3, 6, 10, 12, 14, 16.
5. Pass 5: All elements are already in order, so no more passes are needed.

So, the correct answer is 5.

Knowee AI · Accepted Answer

The number of passes to sort the given numbers using insertion sort will be 5.

Here's the step-by-step process:

1. Pass 1: Compare 14 and 12. Since 12 is smaller, swap them. The list becomes 12, 14, 16, 6, 3, 10.
2. Pass 2: Compare 14 and 16. They are already in order. Then compare 16 and 6. Since 6 is smaller, move 16 to the right and insert 6 before 14. The list becomes 12, 6, 14, 16, 3, 10.
3. Pass 3: Compare 12 and 6. Since 6 is smaller, move 12 to the right and insert 6 at the beginning. Then compare 16 and 3. Since 3 is smaller, move 16, 14, and 12 to the right and insert 3 at the beginning. The list becomes 3, 6, 12, 14, 16, 10.
4. Pass 4: Compare 16 and 10. Since 10 is smaller, move 16 to the right and insert 10 before 14. The list becomes 3, 6, 10, 12, 14, 16.
5. Pass 5: All elements are already in order, so no more passes are needed.

So, the correct answer is 5.

Select the correct answerWhat will be the number of passes to sort 14, 12,16, 6, 3, 10 using insertion sort?Options6715

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