The common difference of an arithmetic progression (A.P.) is found by subtracting the (n-1)th term from the nth term.

Given the nth term of an A.P. as an = 3 + 4n, we can express the (n-1)th term as a(n-1) = 3 + 4(n-1).

Subtracting a(n-1) from an gives:

an - a(n-1) = [3 + 4n] - [3 + 4(n-1)]
= 4n - 4(n-1)
= 4n - 4n + 4
= 4

So, the common difference of the A.P. is 4. Therefore, the correct answer is (c) 4.

Question

The common difference of an arithmetic progression (A.P.) is found by subtracting the (n-1)th term from the nth term.

Given the nth term of an A.P. as an = 3 + 4n, we can express the (n-1)th term as a(n-1) = 3 + 4(n-1).

Subtracting a(n-1) from an gives:

an - a(n-1) = [3 + 4n] - [3 + 4(n-1)]
= 4n - 4(n-1)
= 4n - 4n + 4
= 4

So, the common difference of the A.P. is 4. Therefore, the correct answer is (c) 4.

Knowee AI · Accepted Answer

The common difference of an arithmetic progression (A.P.) is found by subtracting the (n-1)th term from the nth term.

Given the nth term of an A.P. as an = 3 + 4n, we can express the (n-1)th term as a(n-1) = 3 + 4(n-1).

Subtracting a(n-1) from an gives:

an - a(n-1) = [3 + 4n] - [3 + 4(n-1)]
= 4n - 4(n-1)
= 4n - 4n + 4
= 4

So, the common difference of the A.P. is 4. Therefore, the correct answer is (c) 4.

The nth term of an A.P. is given by an = 3 + 4n. The common difference is(a) 7(b) 3(c) 4(d) 1