How many vertical asymptotes does the graph of this function have?𝐹(𝑥)=2𝑥(𝑥+1)F(x)= x(x+1)2 A.1B.2C.0D.3SUBMITarrow_backPREVIOUS
Question
How many vertical asymptotes does the graph of this function have?𝐹(𝑥)=2𝑥(𝑥+1)F(x)= x(x+1)2 A.1B.2C.0D.3SUBMITarrow_backPREVIOUS
Solution
The function given is F(x) = x(x+1)/2.
A vertical asymptote occurs when the denominator of a rational function is equal to zero (since division by zero is undefined).
In this case, the denominator of the function is 2, which is a constant and never equals zero.
Therefore, the function F(x) = x(x+1)/2 has no vertical asymptotes.
So, the answer is C. 0.
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