Compound [A] on chlorination followed by treatment in aqueous alcoholic KOH gives a compound [B], which upon oxidation gives [C]. The compound [C] upon further oxidation followed by treatment with sodalime gives methane. The compound [A] is:ethane propanepropyleneMore than one of the aboveNone of the above
Question
Compound [A] on chlorination followed by treatment in aqueous alcoholic KOH gives a compound [B], which upon oxidation gives [C]. The compound [C] upon further oxidation followed by treatment with sodalime gives methane. The compound [A] is:ethane propanepropyleneMore than one of the aboveNone of the above
Solution
The compound [A] is propylene.
Here's the step by step explanation:
- Chlorination of propylene gives 1,2-dichloropropane.
- Treatment of 1,2-dichloropropane with aqueous alcoholic KOH (a dehydrohalogenation reaction) gives propyne ([B]).
- Oxidation of propyne gives methanal ([C]).
- Further oxidation of methanal gives formic acid.
- Treatment of formic acid with sodalime gives methane.
None of the other options (ethane or propane) would result in methane after these series of reactions.
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