Benzyl alcohol on treatment with this copper-based catalyst gives a compound ‘A’ whichon reaction with KOH gives compounds ‘B’ and ‘C’. Compound ‘B’ on oxidation withKMnO4- KOH gives compound ‘C’. Compounds ‘A’, ‘B’ and ‘C’ respectively are :

An organic compound ‘A’ is having a molecular formula C7H8O. On oxidation with acidifiedKMnO4 it forms compound ‘B’ .Compound ‘B’ can also be obtained from compound C, on itsreaction with NaOH and then with CO2 followed by hydrolysis. Compound C can be easilyformed when butylphenylether is made to react with HI

Compound [A] on chlorination followed by treatment in aqueous alcoholic KOH gives a compound [B], which upon oxidation gives [C]. The compound [C] upon further oxidation followed by treatment with sodalime gives methane. The compound [A] is:ethane propanepropyleneMore than one of the aboveNone of the above

Oxidation of a tertiary alcohol will give Group of answer choicesan aldehydeno producta ketonea carboxylic acid

[A]⟶ reduction [B]⟶CHCl3+KOH[C]⟶ reduction N− Methylaniline, A is?FormaldehydeTrichloromethaneNitrobenzeneToluene

An organic compound [A] which has characteristic odour, reacts with conc. NaOH togive two compounds [B] and [C]. Compound [B] has molecular formula C7H8O whichupon oxidation gives back compound [A]. Compound [C] is the sodium salt of the acidand upon treatment with sodalime yields an aromatic hydrocarbon [D]. Identify thecompounds [A], [B], [C] and [D].