Ramesh travels by bus from city A to city B at an average speed of 44 km/hr. Suresh travels by taxi from city A to city B at an average speed of 77 km/hr and takes 6 hours lesser than time taken by Ramesh. What is the distance (in km) between the two cities?Options₹ 726₹ 560₹ 672₹ 616
Question
Ramesh travels by bus from city A to city B at an average speed of 44 km/hr. Suresh travels by taxi from city A to city B at an average speed of 77 km/hr and takes 6 hours lesser than time taken by Ramesh. What is the distance (in km) between the two cities?Options₹ 726₹ 560₹ 672₹ 616
Solution
Let's solve this step by step:
Step 1: Let's denote the time taken by Ramesh to travel from city A to city B as 't' hours. Therefore, the time taken by Suresh would be 't-6' hours.
Step 2: We know that distance = speed * time. Therefore, the distance travelled by both Ramesh and Suresh would be the same.
So, we can set up the equation as follows:
44t = 77(t-6)
Step 3: Solve the equation:
44t = 77t - 462
Step 4: Rearrange the equation:
77t - 44t = 462
33t = 462
Step 5: Solve for 't':
t = 462 / 33
t = 14 hours
Step 6: Now that we know 't', we can find the distance between the two cities. We can use either Ramesh's or Suresh's speed for this. Let's use Ramesh's speed:
Distance = Speed * Time
Distance = 44 km/hr * 14 hr
Distance = 616 km
So, the distance between the two cities is 616 km. Therefore, the correct option is ₹ 616.
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