Hemophila is a sex-linked recessive disorder. A man with hemophilia mates with a woman who is a carrier for the disease. Complete a Punnett Square of their cross. Insert a table to show work.BoldItalicUnderline
Question
Hemophila is a sex-linked recessive disorder. A man with hemophilia mates with a woman who is a carrier for the disease. Complete a Punnett Square of their cross. Insert a table to show work.BoldItalicUnderline
Solution 1
Sure, let's break this down step by step.
Hemophilia is a sex-linked recessive disorder. This means that it is carried on the X chromosome. Males have one X and one Y chromosome (XY), while females have two X chromosomes (XX).
A man with hemophilia will have the X chromosome carrying the hemophilia gene (we'll denote this as Xh) and a Y chromosome. So his genotype is XhY.
A woman who is a carrier for the disease has one X chromosome with the hemophilia gene and one X chromosome without it. We'll denote the X chromosome without the gene as X. So her genotype is XhX.
Now, let's create a Punnett Square to visualize their potential offspring:
| X | Xh | |
|---|---|---|
| Y | XY | XhY |
| Xh | XhX | XhXh |
From this Punnett Square, we can see that:
- 50% of their male children (XY and XhY) will have hemophilia.
- 50% of their female children (XhX) will be carriers for the disease, and 50% (XhXh) will have the disease.
Please note that I can't insert a table here, but I hope the text representation of the Punnett Square is clear.
Solution 2
Sure, let's break this down step by step.
First, let's define the genotypes of the parents. Hemophilia is a sex-linked recessive disorder, which means it is carried on the X chromosome.
- The man with hemophilia will have the genotype X^hY (where X^h represents the X chromosome with the hemophilia allele and Y represents the Y chromosome).
- The woman is a carrier for the disease, which means she has one normal X chromosome and one X chromosome with the hemophilia allele. Her genotype will be X^HX^h (where X^H represents the normal X chromosome and X^h represents the X chromosome with the hemophilia allele).
Now, let's create a Punnett square to predict the genotypes of their potential offspring.
| X^H | X^h | |
|---|---|---|
| X^h | X^HX^h | X^hX^h |
| Y | X^HY | X^hY |
From this Punnett square, we can see the following:
- 50% of their daughters (X^HX^h) would be carriers of the disease (like their mother).
- 50% of their daughters (X^hX^h) would have the disease.
- 50% of their sons (X^HY) would be normal.
- 50% of their sons (X^hY) would have the disease.
So, there is a 50% chance for each child to have the disease, regardless of their sex.
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