A cricket player bowls a 100g cricket ball, releasing it from a height of exactly 2m. Ignoring the effect of air resistance, if the cricket player wants to release the ball such that its velocity is exactly parallel to the ground. What happens to the horizontal velocity of the ball as it travels?Question 7Answeri.Horizontal velocity is decreasingii.Not enough information is given to me to answer thisiii.Horizontal velocity is increasingiv.Horizontal velocity is constant

A cricket player bowls a 100g cricket ball, releasing it from a height of exactly 2 m. Ignoring the effect of air resistance, if the cricket player wants to release the ball such that its velocity is exactly parallel to the ground. What is the initial vertical velocity of the ball?Question 6Answeri.20 m/sii.10 m/siii.5 m/siv.15 m/sv.0 m/s

A cricket player bowls a 100g cricket ball, releasing it from a height of exactly 1.1m. Ignoring the effect of air resistance, if the cricket player wants to release the ball such that its velocity is exactly parallel to the ground, at what velocity does she need to release it so that it will land 13.8m from the point of release?Note: The height the ball has been released may have changed.Give your answer to one decimal place in units of m/s. Do not include the units in your answer i.e. you would write 8.6 m/s as 8.6

A cricket player bowls a 100g cricket ball, releasing it from a height of exactly 2m. If the cricket player wants to release the ball such that its velocity is exactly parallel to the ground, and the velocity is actually 40 ms-1. Calculate the total mechanical energy of the cricket ball as it is released? Give your answer to zero decimal places in units of J. Do not include the units in your answer i.e. you would write 13 J as 13

. What happens to the horizontal velocity of an object as it travels through the air?

A small ball with mass m is thrown upright vertically at the speed 𝑣₀ . It is assumed that when the ball moves, in addition to gravity, it is always affected by an air resistance of f = kmv^2 Here, k is a constant, and 𝑣 is the speed of the ball. Try to find: (1) the maximum height H that the ball can rise.