The elements of a list are arranged in descending order.Which of the following two will give same outputs? i. print(list_name.sort()) ii. print(max(list_name)) iii. print(list_name.reverse()) iv. print(list_name[-1])i,ii
Question
The elements of a list are arranged in descending order.Which of the following two will give same outputs? i. print(list_name.sort()) ii. print(max(list_name)) iii. print(list_name.reverse()) iv. print(list_name[-1])i,ii
Solution
The correct answer is iii and iv.
Here's why:
i. print(list_name.sort()) - This will sort the list in ascending order, not descending. Also, the sort() function doesn't return anything (it returns None), so printing this will result in None.
ii. print(max(list_name)) - This will print the maximum element in the list, which is the first element if the list is sorted in descending order. But it's not the same as printing the whole list.
iii. print(list_name.reverse()) - The reverse() function doesn't return anything (it returns None), it just reverses the elements in the list. If the list was sorted in descending order, after reversing it will be in ascending order. But printing this will result in None, not the list.
iv. print(list_name[-1]) - This will print the last element in the list. If the list is sorted in descending order, the last element will be the smallest one.
So, the two that will give the same outputs are iii and iv, because both will print None.
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