The kinetic energy (E) of an emitted electron due to the photoelectric effect is given by the equation:

E = hf - Φ

where h is Planck's constant, f is the frequency of the incident light, and Φ is the work function of the metal (the minimum energy needed to remove an electron).

To double the kinetic energy (2E), we need to increase the frequency of the incident light because the work function of the metal remains constant.

However, the frequency (f) and wavelength (λ) of light are inversely related by the equation:

f = c/λ

where c is the speed of light. Therefore, to double the frequency (and thus double the kinetic energy), we need to halve the wavelength of the incident light.

So, the incident light must have a wavelength of λ/2 to double the kinetic energy of the emitted electron.

Question

The kinetic energy (E) of an emitted electron due to the photoelectric effect is given by the equation:

E = hf - Φ

where h is Planck's constant, f is the frequency of the incident light, and Φ is the work function of the metal (the minimum energy needed to remove an electron).

To double the kinetic energy (2E), we need to increase the frequency of the incident light because the work function of the metal remains constant.

However, the frequency (f) and wavelength (λ) of light are inversely related by the equation:

f = c/λ

where c is the speed of light. Therefore, to double the frequency (and thus double the kinetic energy), we need to halve the wavelength of the incident light.

So, the incident light must have a wavelength of λ/2 to double the kinetic energy of the emitted electron.

Knowee AI · Accepted Answer

The kinetic energy (E) of an emitted electron due to the photoelectric effect is given by the equation:

E = hf - Φ

where h is Planck's constant, f is the frequency of the incident light, and Φ is the work function of the metal (the minimum energy needed to remove an electron).

To double the kinetic energy (2E), we need to increase the frequency of the incident light because the work function of the metal remains constant.

However, the frequency (f) and wavelength (λ) of light are inversely related by the equation:

f = c/λ

where c is the speed of light. Therefore, to double the frequency (and thus double the kinetic energy), we need to halve the wavelength of the incident light.

So, the incident light must have a wavelength of λ/2 to double the kinetic energy of the emitted electron.

The kinetic energy of emitted electron is E when the light incident on the metal has wavelength λ.To double the kinetic energy, the incident light must have wavelength:

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