.What will be the output of the following C code?int main() {int arr[] = {1, 2, 3, 4, 5};printf("%d", arr[3]);return 0;}*1 point1234
Question
.What will be the output of the following C code?int main() {int arr[] = {1, 2, 3, 4, 5};printf("%d", arr[3]);return 0;}*1 point1234
Solution
The output of the given C code will be 4.
Here's the step by step explanation:
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An integer array named 'arr' is declared and initialized with the values {1, 2, 3, 4, 5}.
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The printf function is called to print the value at the 3rd index of the array 'arr'.
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In C, array indexing starts from 0. So, arr[0] is 1, arr[1] is 2, arr[2] is 3, arr[3] is 4, and arr[4] is 5.
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Therefore, arr[3] is 4. So, 4 will be printed as the output of this program.
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