Subtract 4p2–3q2+5q–24𝑝2–3𝑞2+5𝑞–2 from 6p2–3pq+7q2+4p–26𝑝2–3𝑝𝑞+7𝑞2+4𝑝–2.A.10p2–3pq+4q2+4p+5q−410𝑝2–3𝑝𝑞+4𝑞2+4𝑝+5𝑞−4B.−2p2+3pq+4q2−4p+5q−2𝑝2+3𝑝𝑞+4𝑞2−4𝑝+5𝑞C.2p2–3pq+4q2+4p−5q−42𝑝2–3𝑝𝑞+4𝑞2+4𝑝−5𝑞−4D.2p2–3pq+10q2+4p–5q

The question seems to be asking to subtract one polynomial from another. Here are the steps to do that:

1. Write down the two polynomials:

   6p^2 - 3pq + 7q^2 + 4p - 2 (let's call this Polynomial A)

   4p^2 - 3q^2 + 5q - 2 (let's call this Polynomial B)

2. Change the signs of the terms in Polynomial B, because we are subtracting it from Polynomial A:

   -4p^2 + 3q^2 - 5q + 2

3. Add the terms of Polynomial A and the sign-changed terms of Polynomial B:

   (6p^2 - 4p^2) + (-3pq) + (7q^2 + 3q^2) + (4p) + (-5q) - 2 + 2

4. Simplify the terms:

   2p^2 - 3pq + 10q^2 + 4p - 5q

So, the answer is 2p^2 - 3pq + 10q^2 + 4p - 5q, which corresponds to option D.