Count the number of tokens in the following C statement: scanf("i=%d", &i);Question 6Answera.6b.9c.8d.7

#include <stdio.h>#include<stdlib.h>int main(){ int n; scanf("%d",&n); int a[n]; for(int i=0;i<n;i++){ scanf("%d",&a[i]); } int m=n/2;… printf("%d",a[j]); } for(int k=m;k<n;k++){ printf("%d",a[k]); } } }

A C program contains the following statements:#include c s t d i o . h>i n t i,j , k;Write an appropriate scanf function to enter numerical values for i, j and k into the computer, assuming(a) The values for i,j and k will be decimal integers not exceeding six characters each.(b) The value for iwill be a decimal integer, j an octal integer and k a hexadecimal integer, with each quantitynot exceeding 8 characters.( c ) The values for iand j will be hexadecimal integers and k will be an octal integer. Each quantity will be 7or fewer characters

123456789#include <stdio.h> int main() { int count = 0; for (int i = 100; i >= 0; i -= 10) { count++; } printf("%d", count); return 0; }

The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i); in c

Write a C program to count number of digits in a number. Using do-while loop