Given that the supply voltage is 230 V (r.m.s.), the frequency is 50 Hz, capacitance of the capacitor is 1000F and the load resistance is 1 k, calculate the ripple factor.
Question
Given that the supply voltage is 230 V (r.m.s.), the frequency is 50 Hz, capacitance of the capacitor is 1000F and the load resistance is 1 k, calculate the ripple factor.
Solution
The ripple factor (γ) for a full-wave rectifier with a capacitor filter can be calculated using the following formula:
γ = 1 / (4√3 * f * R * C)
where:
- f is the frequency,
- R is the load resistance, and
- C is the capacitance.
Given:
- f = 50 Hz,
- R = 1 kΩ = 1000 Ω, and
- C = 1000 µF = 1000 * 10^-6 F.
Substituting these values into the formula, we get:
γ = 1 / (4√3 * 50 * 1000 * 1000 * 10^-6) = 1 / (4 * 1.732 * 50 * 1000 * 10^-3) = 1 / (346.4)
Therefore, the ripple factor is approximately 0.00288 or 0.288%.
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