A digital signal comes from a circuit with 1 ohm source impedance. You probe the signal. The probe presents as 1 ohm over the entire bandwidth of the mesurement setup. What percentage error will you make in the voltage measurement? Enter the answer in % without any signs.
Question
A digital signal comes from a circuit with 1 ohm source impedance. You probe the signal. The probe presents as 1 ohm over the entire bandwidth of the mesurement setup. What percentage error will you make in the voltage measurement? Enter the answer in % without any signs.
Solution
The error in voltage measurement can be calculated using the voltage divider rule. The voltage divider rule states that the voltage across an impedance in a series circuit is equal to the total voltage multiplied by the ratio of the impedance to the total impedance.
In this case, the source impedance is 1 ohm and the probe impedance is also 1 ohm. Therefore, the total impedance is 1 ohm + 1 ohm = 2 ohms.
The voltage across the probe (which is the measured voltage) is equal to the total voltage multiplied by the ratio of the probe impedance to the total impedance. Therefore, the measured voltage is (1 ohm / 2 ohms) = 0.5 of the total voltage.
This means that the measured voltage is 50% of the total voltage. Therefore, the error in the voltage measurement is 100% - 50% = 50%.
So, the percentage error in the voltage measurement is 50%.
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