To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
N is the final amount of the substance,
N0 is the initial amount of the substance,
t is the time that has passed, and
T is the half-life of the substance.

In this case, we want to find N/N0, which is the fraction of the substance that remains after time t. We know that t = 1.21103 years and T = 1600 years.

So, we can plug these values into the formula to get:

N/N0 = (1/2)^(1.21103/1600)

Calculating this gives us:

N/N0 = 0.999548

To express this as a percentage, we multiply by 100, which gives us 99.9548%.

Rounding this to two significant digits gives us 100%.

Question

To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
N is the final amount of the substance,
N0 is the initial amount of the substance,
t is the time that has passed, and
T is the half-life of the substance.

In this case, we want to find N/N0, which is the fraction of the substance that remains after time t. We know that t = 1.21103 years and T = 1600 years.

So, we can plug these values into the formula to get:

N/N0 = (1/2)^(1.21103/1600)

Calculating this gives us:

N/N0 = 0.999548

To express this as a percentage, we multiply by 100, which gives us 99.9548%.

Rounding this to two significant digits gives us 100%.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
N is the final amount of the substance,
N0 is the initial amount of the substance,
t is the time that has passed, and
T is the half-life of the substance.

In this case, we want to find N/N0, which is the fraction of the substance that remains after time t. We know that t = 1.21103 years and T = 1600 years.

So, we can plug these values into the formula to get:

N/N0 = (1/2)^(1.21103/1600)

Calculating this gives us:

N/N0 = 0.999548

To express this as a percentage, we multiply by 100, which gives us 99.9548%.

Rounding this to two significant digits gives us 100%.

Radium-226 is radioactive and has a half life of 1600. years. What percentage of a sample would be left after ×1.21103 years?Round your answer to 2 significant digits.

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